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Q.CH3CH2ClCH_3CH_2Cl undergoes homolytic fission to give

(a) ethyl carbocation and chloride ion
(b) ethyl free radical and chlorine free radical
(c) ethyl carbocation and chlorine free radical
(d) ethyl free radical and chloride ion
Nagaland NbseNagaland Board of School Education (Class XI) 2024MCQ· 1mImportance★★★★★
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Homolysis breaks a covalent bond so that each fragment keeps one electron of the shared pair, producing neutral free radicals — never ions.

In CH3CH2−ClCH_3CH_2-Cl, homolytic fission of the C-Cl bond gives one electron to carbon and one to chlorine: CH3CH2Cl→CH3CH2∙+Cl∙CH_3CH_2Cl \rightarrow CH_3CH_2^{\bullet} + Cl^{\bullet}, i.e. an ethyl free radical and a chlorine free radical. (Heterolytic fission, by contrast, …

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