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Q.Derive the relationship between Cp and Cv for an ideal gas.

Meghalaya MboseMBOSE Meghalaya 11th Board 2022Subjective· 3mImportance★★★★★
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Using H = U + pV = U + nRT for an ideal gas, differentiating with respect to temperature gives Cp − Cv = nR (or Cp − Cv = R per mole).

At constant volume, the heat absorbed equals the increase in internal energy:

qv=Cv dT=dUq_v = C_v\,dT = dU

At constant pressure, the heat absorbed equals the increase in enthalpy:

qp=Cp dT=dHq_p = C_p\,dT = dH

For an ideal gas, enthalpy is defined as:

H=U+pVH = U + pV

Using the ideal gas equation pV=nRTpV = nRT, this becomes:

H=U+nRTH = U + nRT

Differentiating with respect to temperature (n constant):

dH=dU+nR dTdH = dU + nR\,dT

Substituting dH=Cp dTdH = C_p\,dT and dU=Cv dTdU = C_v\,dT: …

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