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Choose the Best Answer · Q16

Q.The value of ΔH\Delta H for cooling 2 moles of an ideal monatomic gas from 125∘125^\circC to 25∘25^\circC at constant pressure will be, given CP=52RC_P=\dfrac{5}{2}R

(a) – 250 R
(b) – 500 R
(c) 500 R
(d) + 250 R
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Step 1. ΔH=nCP(T2−T1)\Delta H=nC_P(T_2-T_1) (Section ~7.6.3, eq. 7.26), with n=2n=2 mol, CP=52RC_P=\tfrac{5}{2}R, T2−T1=25−125=−100T_2-T_1=25-125=-100 (the temperature DROP, since the gas is being cooled). …

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