Skip to content
NCERT Exemplar · Q7

Q.A body of mass 2kg travels according to the law x(t)=pt+qt2+rt3x(t) = pt + qt^2 + rt^3 where p=3p = 3 m s−1^{-1}, q=4q = 4 m s−2^{-2} and r=5r = 5 m s−3^{-3}. The force acting on the body at t=2t = 2 seconds is

(a) 136 N
(b) 134 N
(c) 158 N
(d) 68 N
Meghalaya MboseMCQ· 1mImportance★★★★★est
55% · 42/77 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Newton’s Second Law says force equals mass times acceleration. Differentiate the given position function twice to get acceleration, then multiply by mass. The force at t=2t=2 s is 136 N, option (A).

The core idea is straightforward: force is the product of mass and acceleration. Since the mass is constant (2 kg), the problem reduces to finding the acceleration at the given instant. Acceleration is the second derivative of position with respect to time — so we differentiate the given polynomial twice, evaluate at t=2t=2, and multiply by mass.

  1. Write the position function with the given constants.

    x(t)=3t+4t2+5t3x(t) = 3t + 4t^2 + 5t^3 (all units in SI: metres and seconds).

  2. Find the velocity by differentiating once.

    v(t)=dxdt=3+8t+15t2v(t) = \frac{dx}{dt} = 3 + 8t + 15t^2 m/s.

  3. Find the acceleration by differentiating again.

    a(t)=dvdt=8+30ta(t) = \frac{dv}{dt} = 8 + 30t m/s2^2.

  4. Evaluate acceleration at t=2t=2 seconds.

    a(2)=8+30(2)=8+60=68a(2) = 8 + 30(2) = 8 + 60 = 68 m/s2^2.

  5. Apply Newton’s Second Law: F=maF = ma.

    F=(2 kg)(68 m/s2)=136F = (2 \text{ kg})(68 \text{ m/s}^2) = 136 N. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.