Q.(a) Classify the following as primary/secondary/tertiary alcohols: , and a benzene ring with a -CH2-CH(OH)-CH3 substituent.
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Start your 14-day free trial to unlock the full solution →This question runs through alcohol/ether/phenol classification, ether cleavage, phenol nitration, and alcohol-to-halide conversions (primary branch), or the industrial phenol-from-cumene route together with a chlorobenzene-to-phenol-to-benzene sequence and a Grignard-then-dehydration sequence (alternative branch).
(a) Classification of alcohols:
- (propan-1-ol): the carbon bearing is attached to only one other carbon primary (1°) alcohol.
- Benzene ring— (1-phenylpropan-2-ol): the carbon bearing is attached to two other carbons (the benzylic and the terminal ) secondary (2°) alcohol.
(b)(i) Ether cleavage: (373 K):
On protonation of the ether oxygen, attacks the less hindered (here, methyl) carbon by an pathway, cleaving the C–O bond at the smaller alkyl group:
With excess hot HBr, the resulting propan-1-ol is itself further converted to 1-bromopropane:
(b)(ii) Nitration of phenetole:
The group is strongly activating and ortho/para-directing, so nitration gives a mixture of ortho- and para-nitrophenetole (predominantly para):
(c) Butan-1-ol reactions:
- With (best method — clean, only gaseous by-products):
- With Lucas reagent (conc. + anhydrous ): primary alcohols react only slowly (requiring heating), via an -type displacement: Alternative (Or): (d)(i) Chlorobenzene A B: Under the Dow's process conditions (fused NaOH, 623 K, 300 atm), chlorobenzene is converted to sodium phenoxide, which on acidification (with HCl) gives phenol: Distillation of phenol with zinc dust removes the group (reductive deoxygenation), giving benzene: (d)(ii) C D: Grignard addition of methylmagnesium bromide to acetaldehyde, followed by acidic hydrolysis, gives a secondary alcohol: Acid-catalysed dehydration of this secondary alcohol at 443 K gives the alkene: …
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