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Q.(a) Arrange the following in increasing order of their acid strength: H2OH_2O, CH3OHCH_3OH, C2H5OHC_2H_5OH, C6H5OHC_6H_5OH (1 mark)

(b) Why electrophilic substitution in phenols takes place at ortho- and para-position? (1 mark)
(c) Why are alcohols more soluble in water than hydrocarbons of comparable molecular mass? (1 mark) OR
(d) Give the chemical test to distinguish between phenol and benzoic acid. (1 mark)
(e) Explain the following observations (1+1 = 2 marks):
(i) The boiling point of ethanol is higher than that of methoxymethane.
(ii) Phenol is more acidic than ethanol.
Meghalaya MboseMBOSE Meghalaya Intermediate Board 2022Subjective· 3mImportance★★★★★
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This compares the acidity, reactivity and solubility trends of alcohols and phenol, all traceable to hydrogen bonding and the resonance available (or not) to the −OH-OH group and its conjugate base.

  1. Increasing order of acid strength Acid strength here is judged by how readily the O−HO-H bond releases H+H^+, i.e. by (inverse) pKapK_a (lower pKapK_a = stronger acid). Approximate pKapK_a values: ethanol ≈15.9\approx 15.9, water ≈15.7\approx 15.7, methanol ≈15.5\approx 15.5, phenol ≈10.0\approx 10.0. The alkyl group in ethanol is more electron-donating (+I effect, larger group) than in methanol, which destabilises the alkoxide conjugate base slightly more, making ethanol the weakest acid of the three; phenol is far more acidic than all of them because its conjugate base (phenoxide) is resonance-stabilised (see part (e)(ii) below). Order (weakest → strongest): C2H5OH<H2O<CH3OH<C6H5OHC_2H_5OH < H_2O < CH_3OH < C_6H_5OH.
  2. Why electrophilic substitution occurs at ortho/para in phenol The −OH-OH group on the benzene ring is an activating, ortho/para-directing group. One of the lone pairs on the oxygen atom conjugates with the ring's π\pi-system: resonance structures can be drawn placing extra electron density specifically on the carbon atoms ortho and para to the −OH-OH group. This locally raised electron density makes those two positions the most nucleophilic sites on the ring, so an electrophile (E+E^+) preferentially attacks there rather than at the meta position (where no such resonance-donated charge appears).
  3. Why alcohols are more water-soluble than similar-mass hydrocarbons An alcohol's −OH-OH group can form intermolecular hydrogen bonds with water molecules, a fairly strong, specific intermolecular attraction. A hydrocarbon of comparable molecular mass has no such polar group — it can only engage in weak van der Waals (London dispersion) interactions with water, and in fact disrupts water's own hydrogen-bonded network without compensating for it. Hence alcohols dissolve much more readily in water than hydrocarbons of similar size. …

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