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Q.What happens when D-glucose is treated with the following reagents?

(a) HI
(b) Bromine water
(c) HNO3HNO_3. Give chemical equations.
Meghalaya MboseMBOSE Meghalaya Intermediate Board 2020Subjective· 3mImportance★★★★★
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D-glucose's open-chain form, CHO−(CHOH)4−CH2OHCHO-(CHOH)_4-CH_2OH, reacts differently with each reagent depending on how strongly/selectively that reagent oxidises or reduces its functional groups.

  1. With HI (concentrated, red phosphorus, prolonged heating): this is a strong, exhaustive reduction that removes essentially all the oxygen functionality (converting every −OH-OH/the −CHO-CHO-derived carbon down to −CH2−-CH_2-/−CH3-CH_3), collapsing glucose to the simple unbranched alkane n-hexane — a key piece of historical evidence that glucose's six carbon atoms form a straight chain: CHO−(CHOH)4−CH2OH→ΔHI (red P), excessCH3−(CH2)4−CH3 (n-hexane)CHO-(CHOH)_4-CH_2OH \xrightarrow[\Delta]{HI\ (red\ P),\ excess} CH_3-(CH_2)_4-CH_3\ (n\text{-hexane})
  2. With bromine water: Br2Br_2/water is a mild oxidising agent that selectively oxidises only the aldehyde group (−CHO-CHO) to a carboxylic acid (−COOH-COOH), leaving all the secondary/primary −OH-OH groups untouched, giving the monocarboxylic acid gluconic acid: CHO−(CHOH)4−CH2OH→Br2/H2OCOOH−(CHOH)4−CH2OH (gluconic acid)CHO-(CHOH)_4-CH_2OH \xrightarrow{Br_2/H_2O} COOH-(CHOH)_4-CH_2OH\ (\text{gluconic acid}) …

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