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Q.Write the structure of product formed when D-glucose is treated with NH2OHNH_2OH.

Meghalaya MboseMBOSE Meghalaya Intermediate Board 2024Subjective· 1mImportance★★★★★
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Hydroxylamine reacts with the free aldehyde group of D-glucose in a typical carbonyl condensation, replacing the C=OC=O oxygen with =N−OH=N-OH to give the oxime.

D-glucose exists predominantly in its cyclic hemiacetal form but is in equilibrium with a small amount of the open-chain form, which carries a free aldehyde group at C1:

D-glucose (open chain): CHO−(CHOH)4−CH2OHD\text{-glucose (open chain)}: \ CHO-(CHOH)_4-CH_2OH

Hydroxylamine, NH2OHNH_2OH, is a classic carbonyl-reactive reagent: its nucleophilic nitrogen attacks the aldehyde carbon, and after loss of a water molecule, the C=OC=O is converted into a C=N−OHC=N-OH (oxime) linkage:

CHO−(CHOH)4−CH2OH+NH2OH⟶CH=NOH−(CHOH)4−CH2OH+H2OCHO-(CHOH)_4-CH_2OH + NH_2OH \longrightarrow CH{=}NOH-(CHOH)_4-CH_2OH + H_2O

i.e. glucose oxime: CH2OH−(CHOH)4−CH=N−OHCH_2OH-(CHOH)_4-CH=N-OH.

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