Q.The locus of a point for which is
(A) -plane
(B) -plane
(C) -plane
(D) none of these
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Start your 14-day free trial to unlock the full solution →The condition fixes the -coordinate to zero while and can vary freely. This describes the -plane in 3D space. The correct option is (B).
Why This Works
In three-dimensional coordinate geometry, every point is represented by an ordered triple . The equation means the -coordinate is always zero, but and can take any real value. So the set of all points satisfying this is .
Think of the familiar -plane: that's where , and and are free. By exact analogy, gives the plane perpendicular to the -axis at the origin — the -plane. Every point on this plane has its -coordinate locked at zero.
A common mistake is to confuse with the -plane. The -plane is given by , not . Keep the coordinate axes straight: the plane named after the two axes that vary.
Step-by-Step Reasoning
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Interpret the condition.
The equation imposes a restriction only on the -coordinate. The coordinates and are unrestricted — they can be any real numbers.
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Visualise the set of points.
All points of the form lie on a plane that contains the -axis and the -axis. This plane passes through the origin and is perpendicular to the -axis.
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Name the plane. …
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