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Miscellaneous Exercise · Q13

Q.How many litres of water will have to be added to 1125 litres of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?

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Diluting acid with water decreases concentration; we set up inequalities for the final percentage and solve for the volume of water that keeps the acid content strictly between 25% and 30%. The answer is more than 562.5 litres but less than 900 litres.

Understanding Mixture Concentration

When you add pure water to an acid solution, the amount of pure acid stays constant—only the total volume increases. This dilution lowers the concentration. If we start with 1125 litres of a 45% acid solution, the pure acid present is 1125×0.45=506.251125 \times 0.45 = 506.25 litres. Adding xx litres of water gives a new total volume of (1125+x)(1125 + x) litres, but the acid remains 506.25 litres. The new concentration becomes 506.251125+x\frac{506.25}{1125 + x}.

We want this new concentration to lie strictly between 25% and 30%, which translates to the double inequality:

0.25<506.251125+x<0.300.25 < \frac{506.25}{1125 + x} < 0.30

Let's solve each part separately.


Step-by-Step Solution

1. Calculate the pure acid in the original solution

The original solution is 45% acid:

Pure acid=1125×0.45=506.25 litres\text{Pure acid} = 1125 \times 0.45 = 506.25 \text{ litres}

2. Set up the inequality for "more than 25%"

We need:

506.251125+x>0.25\frac{506.25}{1125 + x} > 0.25

Multiply both sides by (1125+x)(1125 + x) (which is positive, so the inequality direction stays the same):

506.25>0.25(1125+x)506.25 > 0.25(1125 + x)

506.25>281.25+0.25x506.25 > 281.25 + 0.25x

506.25−281.25>0.25x506.25 - 281.25 > 0.25x

225>0.25x225 > 0.25x

x<2250.25=900x < \frac{225}{0.25} = 900

So we need x<900x < 900 litres.

3. Set up the inequality for "less than 30%"

We need:

506.251125+x<0.30\frac{506.25}{1125 + x} < 0.30

Multiply both sides by (1125+x)(1125 + x):

506.25<0.30(1125+x)506.25 < 0.30(1125 + x)

506.25<337.5+0.30x506.25 < 337.5 + 0.30x

506.25−337.5<0.30x506.25 - 337.5 < 0.30x

168.75<0.30x168.75 < 0.30x

x>168.750.30=562.5x > \frac{168.75}{0.30} = 562.5

So we need x>562.5x > 562.5 litres. …

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