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Worked Examples · Example 12
Q.

Let N\mathbb{N} be the set of natural numbers. Define a real valued function f:N→Nf : \mathbb{N} \to \mathbb{N} by f(x)=2x+1f(x) = 2x + 1. Using this definition, complete the table given below.

xx1234567
yyf(1)=…f(1) = \ldotsf(2)=…f(2) = \ldotsf(3)=…f(3) = \ldotsf(4)=…f(4) = \ldotsf(5)=…f(5) = \ldotsf(6)=…f(6) = \ldotsf(7)=…f(7) = \ldots
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Substitute each natural number into f(x)=2x+1f(x) = 2x + 1 to find the corresponding output; the function doubles the input and adds one, producing the sequence of odd numbers starting from 3.

Understanding Function Evaluation

A function is a rule that assigns to each input exactly one output. When we write f(x)=2x+1f(x) = 2x + 1, we're saying: "take whatever number xx is, multiply it by 2, then add 1."

The notation f(1)f(1) means "apply this rule to the input 1." So we substitute x=1x = 1 into the formula and compute. The same process works for any input value.

Notice something interesting about this particular function: it takes natural numbers and produces odd numbers. Since we're doubling (always even) and adding 1, the result must be odd. This is why f:N→Nf : \mathbb{N} \to \mathbb{N} makes sense—odd numbers are still natural numbers.

Step-by-Step Evaluation

Let me work through each value systematically:

  1. For x=1x = 1:

    f(1)=2(1)+1=2+1=3f(1) = 2(1) + 1 = 2 + 1 = 3

  2. For x=2x = 2:

    f(2)=2(2)+1=4+1=5f(2) = 2(2) + 1 = 4 + 1 = 5

  3. For x=3x = 3:

    f(3)=2(3)+1=6+1=7f(3) = 2(3) + 1 = 6 + 1 = 7

  4. For x=4x = 4:

    f(4)=2(4)+1=8+1=9f(4) = 2(4) + 1 = 8 + 1 = 9

  5. For x=5x = 5:

    f(5)=2(5)+1=10+1=11f(5) = 2(5) + 1 = 10 + 1 = 11

  6. For x=6x = 6:

    f(6)=2(6)+1=12+1=13f(6) = 2(6) + 1 = 12 + 1 = 13

  7. For x=7x = 7:

    f(7)=2(7)+1=14+1=15f(7) = 2(7) + 1 = 14 + 1 = 15 …

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