Skip to content
Miscellaneous Examples · Example 20

Q.Let f={(1,1),(2,3),(0,−1),(−1,−3)}f = \{(1, 1), (2, 3), (0, -1), (-1, -3)\} be a linear function from Z\mathbb{Z} into Z\mathbb{Z}. Find f(x)f(x).

Mizoram MbseTextbookSubjective· 2mImportance★★★★★est
44% · 44/100 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Since ff is linear from Z\mathbb{Z} to Z\mathbb{Z}, it must be of the form f(x)=ax+bf(x) = ax + b. Using two given points to solve for aa and bb, we find f(x)=2x−1f(x) = 2x - 1.

A linear function from Z\mathbb{Z} to Z\mathbb{Z} means f(x)=ax+bf(x) = ax + b, where aa and bb are integers. The set ff gives us four points that lie on this line: (1,1)(1,1), (2,3)(2,3), (0,−1)(0,-1), and (−1,−3)(-1,-3). Any two distinct points are enough to determine the line uniquely — the other two serve as a consistency check.

Let’s work through it.

  1. Use the general form.

    Since ff is linear, write f(x)=ax+bf(x) = ax + b with a,b∈Za, b \in \mathbb{Z}.

  2. Plug in two points to get equations.

    Take (1,1)(1, 1):

1=a(1)+b⇒a+b=11 = a(1) + b \quad \Rightarrow \quad a + b = 1

Take (2,3)(2, 3):

3=a(2)+b⇒2a+b=33 = a(2) + b \quad \Rightarrow \quad 2a + b = 3

  1. Solve the system. Subtract the first equation from the second:

(2a+b)−(a+b)=3−1⇒a=2(2a + b) - (a + b) = 3 - 1 \quad \Rightarrow \quad a = 2

Substitute a=2a = 2 into a+b=1a + b = 1:

2+b=1⇒b=−12 + b = 1 \quad \Rightarrow \quad b = -1

So f(x)=2x−1f(x) = 2x - 1.

  1. Verify with the remaining points.

    For (0,−1)(0, -1): 2(0)−1=−12(0) - 1 = -1 ✓

    For (−1,−3)(-1, -3): 2(−1)−1=−32(-1) - 1 = -3 ✓

    All four points satisfy f(x)=2x−1f(x) = 2x - 1, confirming consistency. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.