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NCERT Exemplar · Q68

Q.Assertion: The C-O-C bond angle in ethers is slightly less than the tetrahedral angle.
Reason: There is a repulsion between the two bulky (-R) groups.

(i) Assertion and reason both are correct statements and reason is the correct explanation for assertion.
(ii) Assertion and reason both are correct statements but reason is not the correct explanation for assertion.
(iii) Assertion is correct statement but reason is wrong statement.
(iv) Assertion is wrong statement but reason is correct statement.
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The C-O-C bond angle in ethers is slightly greater than the tetrahedral angle (about 110°–112°), not less. The repulsion between bulky alkyl groups actually increases the angle. So the assertion is wrong, but the reason (repulsion between bulky groups) is correct. The answer is (iv).

Why this question trips students up

Most students memorise that ethers have a bent shape around oxygen, and they vaguely recall "tetrahedral angle = 109.5°". The trap is assuming that because oxygen has two lone pairs (like in water), the bond angle must be smaller than tetrahedral — just like water's angle is 104.5°. But ethers are not water. The key difference: in ethers, the two groups attached to oxygen are alkyl groups (R), not hydrogens. Those alkyl groups are bulky and repel each other, pushing the C-O-C angle open.

Let's break it down properly.


  1. Recall the reference: the tetrahedral angle

    In a perfect tetrahedron (e.g., methane, CH₄), the bond angle is 109.5∘109.5^\circ. This is the angle when four identical groups are equally spaced around a central atom.

  2. What is the actual C-O-C bond angle in ethers?

    In dimethyl ether (CH₃–O–CH₃), the C-O-C bond angle is about 111∘111^\circ–112∘112^\circ. In diethyl ether, it's around 110∘110^\circ. These are slightly greater than 109.5∘109.5^\circ, not less.

  3. Why is it greater, not smaller?

    Oxygen in ethers is sp3sp^3 hybridised — it has two bond pairs (to the two R groups) and two lone pairs. Lone pairs repel more strongly than bond pairs (VSEPR theory). That repulsion would normally compress the bond angle (as in water, where lone pair–lone pair repulsion gives 104.5∘104.5^\circ).

    But here, the two R groups are large and bulky. Their steric repulsion overcomes the lone pair compression, forcing the C-O-C angle to open up beyond 109.5∘109.5^\circ.

Tip

Think of it like this: lone pairs want to squeeze the angle shut; bulky groups want to push it open. In ethers, the bulky groups win. In water, there are no bulky groups — only hydrogens — so lone pairs dominate and the angle shrinks.

  1. Evaluate the Assertion …

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