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Q.A golf ball has a mass of 40g and a speed of 45 ms⁻¹. If the speed can be measured within accuracy of 2%, calculate the uncertainty in position. (h = 6.626×10⁻³⁴ kg m² s⁻¹).

Nagaland NbseNagaland Board of School Education (Class XI) 2023Subjective· 3mImportance★★★★★
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Using Heisenberg's uncertainty principle, the uncertainty in the golf ball's position works out to about 1.46×10−33 m1.46\times10^{-33}\,m — an immeasurably tiny number, showing the principle is negligible for macroscopic objects.

Given: m=40 g=0.040 kgm = 40\,g = 0.040\,kg, v=45 ms−1v = 45\,ms^{-1}, uncertainty in speed =2%= 2\% of vv.

Δv=0.02×45=0.9 ms−1\Delta v = 0.02 \times 45 = 0.9\,ms^{-1}

Uncertainty in momentum:

Δp=mΔv=0.040×0.9=0.036 kg m s−1\Delta p = m\Delta v = 0.040 \times 0.9 = 0.036\,kg\,m\,s^{-1}

Heisenberg's uncertainty principle:

Δx⋅Δp≥h4π\Delta x \cdot \Delta p \geq \frac{h}{4\pi}

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