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Exercise 10.3 · Q8

Q.Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse 16x2+y2=1616x^2 + y^2 = 16.

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Rewrite the ellipse in standard form x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 to identify aa and bb, then use the relationship b2=a2(1−e2)b^2 = a^2(1 - e^2) to find all characteristic elements. Here a=4a = 4, b=1b = 1, giving a vertical major axis along the yy-axis.

The equation 16x2+y2=1616x^2 + y^2 = 16 describes an ellipse, but not in the form we can immediately read. An ellipse in standard position has the form x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, where the denominators tell us the semi-axis lengths. The larger denominator corresponds to the major axis. Once we identify aa (semi-major) and bb (semi-minor), the geometry follows: the foci lie along the major axis at a distance c=a2−b2c = \sqrt{a^2 - b^2} from the center, the eccentricity is e=cae = \frac{c}{a}, and the latus rectum (the chord through a focus perpendicular to the major axis) has length 2b2a\frac{2b^2}{a}.

Let's extract everything systematically.


Step-by-step solution

  1. Rewrite in standard form Divide both sides of 16x2+y2=1616x^2 + y^2 = 16 by 1616:

16x216+y216=1⇒x21+y216=1.\frac{16x^2}{16} + \frac{y^2}{16} = 1 \quad \Rightarrow \quad \frac{x^2}{1} + \frac{y^2}{16} = 1.

This is now in the form x2b2+y2a2=1\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 with b2=1b^2 = 1 and a2=16a^2 = 16.

  1. Identify the semi-axes

    Since a2=16>b2=1a^2 = 16 > b^2 = 1, the major axis lies along the yy-direction.

    We have a=4a = 4 (semi-major axis) and b=1b = 1 (semi-minor axis).

  2. Find the distance to the foci

    For an ellipse, c2=a2−b2c^2 = a^2 - b^2:

c2=16−1=15⇒c=15.c^2 = 16 - 1 = 15 \quad \Rightarrow \quad c = \sqrt{15}.

The foci lie on the major axis, which is the yy-axis, at (0,±c)(0, \pm c).

  1. Locate the vertices

    The vertices are the endpoints of the major axis, at (0,±a)=(0,±4)(0, \pm a) = (0, \pm 4).

  2. Compute the lengths of the axes

    • Major axis: 2a=2×4=82a = 2 \times 4 = 8.
    • Minor axis: 2b=2×1=22b = 2 \times 1 = 2.
  3. Calculate the eccentricity

    The eccentricity measures how "stretched" the ellipse is:

e=ca=154.e = \frac{c}{a} = \frac{\sqrt{15}}{4}.

  1. Find the length of the latus rectum …

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