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Q.Find the point on the yy-axis which is equidistant from the points A(3,1,2)(3, 1, 2) and B(5,5,2)(5, 5, 2).

Nagaland NbseNagaland Board of School Education (Class XI) 2024Subjective· 2mImportance★★★★★
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A point on the yy-axis has the form (0,y,0)(0,y,0); equate its squared distances from A and B and solve for yy.

Let the required point be P(0,y,0)P(0,y,0).

PA2=(0−3)2+(y−1)2+(0−2)2=9+(y−1)2+4=13+(y−1)2PA^2 = (0-3)^2+(y-1)^2+(0-2)^2 = 9+(y-1)^2+4 = 13+(y-1)^2

PB2=(0−5)2+(y−5)2+(0−2)2=25+(y−5)2+4=29+(y−5)2PB^2 = (0-5)^2+(y-5)^2+(0-2)^2 = 25+(y-5)^2+4 = 29+(y-5)^2

Since PA=PBPA=PB, set PA2=PB2PA^2=PB^2:

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