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Q.A TV tower has height 'h'. Derive an expression for the maximum distance up to which the signal can be received from the antenna. What is the area and population covered by the signal?

Nagaland NbseNagaland Board of School Education 2021Subjective· 3mImportance★★★★★
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The transmitting antenna's range is limited by the geometric horizon: d=2Rhd=\sqrt{2Rh}, giving coverage area A=2πRhA=2\pi Rh and population =A×(population density)=A\times(\text{population density}).

For ground-wave/line-of-sight (space-wave) transmission such as TV broadcast, the signal from an antenna of height hh mounted on a tower can only reach receivers within the geometric line of sight, since it cannot bend around the curved earth (unlike ground waves at low frequencies). This maximum straight-line distance to the horizon is limited by earth's curvature.

Derivation of maximum range dd: Consider the earth as a sphere of radius RR, with a transmitting antenna of height hh at point T on its surface. The line of sight from the top of the tower to the horizon point M is tangent to the earth's surface at M, so OM (the earth's radius, RR) is perpendicular to TM (the line of sight) at M. In right triangle OMT:

OT2=OM2+MT2  ⟹  (R+h)2=R2+d2OT^2 = OM^2 + MT^2 \implies (R+h)^2 = R^2 + d^2

R2+2Rh+h2=R2+d2  ⟹  d2=2Rh+h2R^2 + 2Rh + h^2 = R^2 + d^2 \implies d^2 = 2Rh + h^2

Since the tower height hh is very small compared to the earth's radius RR (a few hundred metres versus R≈6400R\approx6400 km), h2≪2Rhh^2 \ll 2Rh, so it is neglected:

d≈2Rhd \approx \sqrt{2Rh}

Area covered: The signal reaches every point within this radius dd around the base of the tower, so the coverage is a circle of radius dd: …

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