Skip to content
Question of 34

Q.Deduce an expression for the magnetic dipole moment of an electron orbiting around the central nucleus.

Nagaland NbseNagaland Board of School Education 2019Subjective· 2mImportance★★★★★
0% · 0/34 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Modelling the orbiting electron as a current loop gives magnetic moment μ=evr/2=(e/2m)L\mu=evr/2=(e/2m)L.

Consider an electron of charge −e-e (magnitude ee) revolving in a circular orbit of radius rr around the nucleus with constant speed vv. The time for one revolution (period) is

T=2πrvT = \dfrac{2\pi r}{v}

Since the electron passes any point on the orbit once every period TT, this circulating charge is equivalent to a steady current

I=eT=ev2πrI = \dfrac{e}{T} = \dfrac{ev}{2\pi r}

This current loop encloses an area A=πr2A=\pi r^2, so it possesses an orbital magnetic dipole moment

μl=IA=(ev2πr)(πr2)=evr2\mu_l = IA = \left(\dfrac{ev}{2\pi r}\right)(\pi r^2) = \dfrac{evr}{2}

In terms of angular momentum: The orbital angular momentum of the electron is L=mvrL=mvr, so vr=L/mvr=L/m. Substituting: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.