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I. Multiple Choice Questions · Q10

Q.A non-conducting charged ring carrying a charge of qq, mass mm, and radius rr is rotated about its own axis with constant angular speed ω\omega. Find the ratio of its magnetic moment to its angular momentum.

(a) qm\dfrac{q}{m}
(b) 2qm\dfrac{2q}{m}
(c) q2m\dfrac{q}{2m}
(d) q4m\dfrac{q}{4m}
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Step 1. A ring of charge qq rotating with angular speed ω\omega carries an effective current I=q×ω2πI = q\times\dfrac{\omega}{2\pi} (charge qq passes any fixed point once every period T=2π/ωT=2\pi/\omega).

Step 2. Its magnetic moment, using μ=IA\mu=IA with A=πr2A=\pi r^2, is

μ=qω2π×πr2=qωr22\mu = \frac{q\omega}{2\pi}\times\pi r^2 = \frac{q\omega r^2}{2} …

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