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Question 37 of 37

Q.(a) Explain with the help of suitable diagram, the two processes which occur during the formations of a p-n junction diode. Hence define the terms

(i) depletion region and
(ii) potential barrier.
(b) Draw a circuit diagram of a p-n junction diode under forward bias and explain its working. OR
(a) Describe briefly three factors which justify the need for modulation of audio frequency signals over long distances in communication.
(b) Draw the waveforms of
(i) carrier wave,
(ii) a modulating signal and
(iii) amplitude modulated wave.
Nagaland NbseCBSE Class XII Board 2018Subjective· 5mImportance★★★★★
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Formation of a p-n junction: diffusion and drift create a depletion region of fixed ions and a built-in potential barrier across the junction.
Formation of a p-n junction: diffusion and drift create a depletion region of fixed ions and a built-in potential barrier across the junction.

Diffusion + drift →\rightarrow depletion region + potential barrier; forward bias lowers the barrier and current flows. (OR: modulation is needed for practical antenna size, adequate radiated power, and to avoid signal mixing; draw carrier, modulating and AM waveforms.)

(a) Formation of a p-n junction. Two processes occur:

  1. Diffusion: because of the concentration gradient, majority holes diffuse from p→\ton and majority electrons diffuse from n→\top, leaving behind immobile negative acceptor ions on the p-side and positive donor ions on the n-side.
  2. Drift: these immobile ions set up an electric field (n positive, p negative) that drives minority carriers in the opposite direction (drift). Equilibrium is reached when diffusion and drift currents balance.
  • (i) Depletion region: the thin region on either side of the junction that is depleted of free/mobile charge carriers, containing only fixed ionised donors and acceptors.
  • (ii) Potential barrier: the built-in potential difference developed across the depletion region (n-side higher, p-side lower) that opposes further diffusion of majority carriers.

(b) Forward bias. Connect the p-side to the + terminal and n-side to the − terminal of a battery. The external field opposes the built-in field, so the depletion width decreases and the barrier potential is reduced. Majority carriers are pushed across the junction, and a large forward current flows that rises steeply once the applied voltage exceeds the barrier (knee) voltage. (Circuit to draw: diode with p to battery +, n to −, in series with a resistor and a milliammeter.)

OR-alternative (need for modulation). …

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