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NCERT Exemplar · Q58

Q.Derive the relationship between ΔH and ΔU for an ideal gas. Explain each term involved in the equation.

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For an ideal gas, the enthalpy change ΔH\Delta H and internal energy change ΔU\Delta U are related by ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT, where Δng\Delta n_g is the change in moles of gas. This arises because enthalpy is defined as H=U+PVH = U + PV, and for an ideal gas PV=nRTPV = nRT.

The relationship between ΔH\Delta H and ΔU\Delta U is one of the most fundamental ideas in thermochemistry. It tells you how much of the heat absorbed or released in a reaction goes into changing the internal energy of the system versus doing pressure-volume work on the surroundings. For an ideal gas, this relationship takes a particularly clean and useful form.

Let’s start with the definition of enthalpy. Enthalpy HH is defined as:

H=U+PVH = U + PV

where UU is the internal energy, PP is the pressure, and VV is the volume. This definition is not arbitrary — it’s constructed so that at constant pressure, the heat exchanged equals the change in enthalpy. For a change from an initial state to a final state, the change in enthalpy is:

ΔH=ΔU+Δ(PV)\Delta H = \Delta U + \Delta(PV)

Now, for an ideal gas, we have the equation of state PV=nRTPV = nRT. So PVPV is not a constant — it depends on the number of moles nn and the temperature TT. If the temperature is constant (which is often the case in calorimetry, or when we compare ΔH\Delta H and ΔU\Delta U at the same temperature), then:

Δ(PV)=Δ(nRT)=RTΔn\Delta(PV) = \Delta(nRT) = RT \Delta n

Here, Δn\Delta n is the change in the number of moles of gas during the reaction. But careful: this Δn\Delta n is specifically the change in gaseous moles only — solids and liquids contribute negligibly to PVPV compared to gases.

So the relationship becomes:

ΔH=ΔU+RTΔng\Delta H = \Delta U + RT \Delta n_g

where Δng=ngaseous products−ngaseous reactants\Delta n_g = n_{\text{gaseous products}} - n_{\text{gaseous reactants}}.

Let’s break down each term:

  1. ΔH\Delta H — Enthalpy change. This is the heat absorbed or released at constant pressure. In bomb calorimetry, we measure ΔU\Delta U directly (constant volume), but most reactions in open containers occur at constant pressure, so ΔH\Delta H is what we usually want.

  2. ΔU\Delta U — Internal energy change. This accounts for changes in bond energies, molecular motions, and interactions. At constant volume, no work is done, so ΔU=qV\Delta U = q_V (heat at constant volume).

  3. RTΔngRT \Delta n_g — The work term. This is the PΔVP\Delta V work done by (or on) the system as the number of gas moles changes. If Δng>0\Delta n_g > 0 (more gas moles produced), the system expands against the atmosphere, doing work, so ΔH>ΔU\Delta H > \Delta U — some of the heat goes into work. If Δng<0\Delta n_g < 0, the surroundings do work on the system, so ΔH<ΔU\Delta H < \Delta U.

Tip

A quick way to remember: ΔH\Delta H and ΔU\Delta U differ only when the number of gas molecules changes. For reactions with no gas, or where the number of gas moles is the same on both sides, ΔH=ΔU\Delta H = \Delta U. …

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