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Miscellaneous Examples · Example 7

Q.Find the conjugate of (3−2i)(2+3i)(1+2i)(2−i)\dfrac{(3 - 2i)(2 + 3i)}{(1 + 2i)(2 - i)}.

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✓ Free question

Simplify the fraction to a+iba+ib form, then flip the sign of the imaginary part. The conjugate is 6325+1625i\dfrac{63}{25} + \dfrac{16}{25}i.

Simplify the numerator and denominator.

Numerator: (3−2i)(2+3i)=6+9i−4i−6i2=6+5i+6=12+5i.(3-2i)(2+3i) = 6+9i-4i-6i^2 = 6+5i+6 = 12+5i.

Denominator: (1+2i)(2−i)=2−i+4i−2i2=2+3i+2=4+3i.(1+2i)(2-i) = 2-i+4i-2i^2 = 2+3i+2 = 4+3i.

So

z=12+5i4+3i.z = \frac{12+5i}{4+3i}.

Put zz in standard form. Multiply by the conjugate 4−3i4-3i:

z=(12+5i)(4−3i)(4+3i)(4−3i)=48−36i+20i−15i216+9=48−16i+1525=63−16i25.z = \frac{(12+5i)(4-3i)}{(4+3i)(4-3i)} = \frac{48-36i+20i-15i^2}{16+9} = \frac{48-16i+15}{25} = \frac{63-16i}{25}.

Take the conjugate. Flip the sign of the imaginary part:

z‾=63+16i25=6325+1625i.\overline{z} = \frac{63+16i}{25} = \frac{63}{25} + \frac{16}{25}i.

✓Final answer

The conjugate is 6325+1625i.\dfrac{63}{25} + \dfrac{16}{25}i.

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