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NCERT Exemplar · Q17

Q.If xx is a real number and ∣x∣<3|x| < 3, then
(A) x≥3x \ge 3
(B) −3<x<3-3 < x < 3
(C) x≤−3x \le -3
(D) −3≤x≤3-3 \le x \le 3

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The absolute value inequality ∣x∣<3|x| < 3 means the distance of xx from 0 is less than 3, so xx lies strictly between −3-3 and 33. The correct option is (B).

The key to solving ∣x∣<3|x| < 3 is understanding what absolute value actually means. It’s not just a “make everything positive” button — it’s a distance. ∣x∣|x| is the distance of xx from 0 on the number line. So ∣x∣<3|x| < 3 says: “The distance from xx to 0 is less than 3.”

That immediately tells you xx cannot be 3 or more, because then its distance would be at least 3. It also cannot be −3-3 or less, because the distance from −3-3 to 0 is exactly 3, and from −4-4 it’s 4, which is greater than 3. So xx must be somewhere in between — strictly between −3-3 and 33.

Let’s walk through it step by step.

  1. Rewrite the inequality in words.

    ∣x∣<3|x| < 3 means the distance of xx from 0 is less than 3 units.

  2. Translate that into a compound inequality.

    If a number’s distance from 0 is less than 3, it must be greater than −3-3 and less than 33 at the same time.

    So: −3<x<3-3 < x < 3.

  3. Check the boundaries.

    If x=3x = 3, then ∣3∣=3|3| = 3, which is not less than 3 — it’s equal. So x=3x = 3 is not allowed. Similarly, x=−3x = -3 gives ∣−3∣=3|-3| = 3, also not allowed. That’s why the inequality is strict: << not ≤\le.

  4. Match with the options.

    • (A) x≥3x \ge 3 is the opposite — it’s outside the range. …

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