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Exercise 13.1 · Q2

Q.Find the mean deviation about the mean for the following data: 38, 70, 48, 40, 42, 55, 63, 46, 54, 44

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Mean deviation about the mean measures the average absolute distance of each data point from the arithmetic mean. For this data, the mean is 5050, and the mean deviation is 8.48.4.

The mean deviation about the mean is a measure of dispersion that tells us, on average, how far each observation lies from the centre of the data. Unlike variance, it uses absolute values, so it treats deviations in both directions equally without squaring them. This makes it more intuitive but mathematically less convenient for further analysis.

Here’s how we find it, step by step.

  1. Find the mean of the data. The data set is: 38,70,48,40,42,55,63,46,54,4438, 70, 48, 40, 42, 55, 63, 46, 54, 44. There are n=10n = 10 observations. Sum of all values:

38+70+48+40+42+55+63+46+54+4438 + 70 + 48 + 40 + 42 + 55 + 63 + 46 + 54 + 44

Let’s add carefully:

38+70=10838 + 70 = 108

108+48=156108 + 48 = 156

156+40=196156 + 40 = 196

196+42=238196 + 42 = 238

238+55=293238 + 55 = 293

293+63=356293 + 63 = 356

356+46=402356 + 46 = 402

402+54=456402 + 54 = 456

456+44=500456 + 44 = 500

So the sum is 500500.

Mean xˉ=50010=50\bar{x} = \frac{500}{10} = 50.

  1. Find the absolute deviations from the mean.

    For each observation xix_i, compute ∣xi−xˉ∣|x_i - \bar{x}|:

    | xix_i | xi−50x_i - 50 | ∣xi−50∣|x_i - 50| |

    |-------|------------|--------------|

    | 38 | −12-12 | 12 |

    | 70 | 2020 | 20 |

    | 48 | −2-2 | 2 |

    | 40 | −10-10 | 10 |

    | 42 | −8-8 | 8 |

    | 55 | 55 | 5 |

    | 63 | 1313 | 13 |

    | 46 | −4-4 | 4 |

    | 54 | 44 | 4 |

    | 44 | −6-6 | 6 |

    Notice that the negative signs disappear — that’s the whole point of taking absolute values.

  2. Sum the absolute deviations.

12+20+2+10+8+5+13+4+4+612 + 20 + 2 + 10 + 8 + 5 + 13 + 4 + 4 + 6

Add them:

12+20=3212 + 20 = 32

32+2=3432 + 2 = 34

34+10=4434 + 10 = 44

44+8=5244 + 8 = 52

52+5=5752 + 5 = 57

57+13=7057 + 13 = 70

70+4=7470 + 4 = 74

74+4=7874 + 4 = 78

78+6=8478 + 6 = 84

Total = 8484.

  1. Divide by the number of observations. Mean deviation about the mean = 8410=8.4\frac{84}{10} = 8.4.
Watch out

A common mistake is to forget the absolute value and let negative deviations cancel out. That would give a sum of 00 — which is always true for deviations from the mean, but tells you nothing about spread. Always take absolute values before summing.

Tip

If the numbers are large, you can first subtract a constant (like 5050) from every value to simplify the arithmetic. The mean shifts by that constant, and the absolute deviations remain unchanged. Here, the numbers were already friendly, so no shortcut was needed.

✓Final answer

The mean deviation about the mean is 8.4\boxed{8.4}.

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