Skip to content
NCERT Exemplar · Q4

Q.Find the equation of the lines which passes through the point (3,4)(3,4) and cuts off intercepts from the coordinate axes such that their sum is 14.

Odisha ChseShort· 3mImportance★★★★★est
62% · 90/145 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Two lines satisfy the conditions: x+y=7x + y = 7 and 4x+3y=244x + 3y = 24.

Let the line make intercepts aa and bb on the axes, so its equation is

xa+yb=1,a+b=14 ⇒ b=14−a.\frac{x}{a} + \frac{y}{b} = 1,\qquad a + b = 14 \ \Rightarrow\ b = 14 - a.

Since it passes through (3,4)(3, 4):

3a+414−a=1.\frac{3}{a} + \frac{4}{14-a} = 1.

Clearing denominators:

3(14−a)+4a=a(14−a) ⇒ 42+a=14a−a2 ⇒ a2−13a+42=0.3(14-a) + 4a = a(14-a)\ \Rightarrow\ 42 + a = 14a - a^2\ \Rightarrow\ a^2 - 13a + 42 = 0.

(a−6)(a−7)=0 ⇒ a=6 or a=7.(a-6)(a-7) = 0 \ \Rightarrow\ a = 6 \ \text{or}\ a = 7. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.