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Exercise 9.2 · Q12

Q.Find equation of the line passing through the point (2,2)(2, 2) and cutting off intercepts on the axes whose sum is 99.

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Using the intercept form xa+yb=1\frac{x}{a} + \frac{y}{b} = 1 with a+b=9a + b = 9 and the point (2,2)(2,2) on the line gives two lines: 2x+y=62x + y = 6 and x+2y=6x + 2y = 6.

Step-by-step solution

1. Intercept form. Let the intercepts be aa and bb:

xa+yb=1\frac{x}{a} + \frac{y}{b} = 1

2. Sum condition. a+b=9a + b = 9, so b=9−ab = 9 - a.

3. Point condition. Substituting (2,2)(2,2):

2a+2b=1\frac{2}{a} + \frac{2}{b} = 1

4. Combine. Multiplying by abab: 2b+2a=ab2b + 2a = ab, i.e. 2(a+b)=ab2(a+b) = ab. With a+b=9a + b = 9:

ab=18ab = 18

5. Solve. aa and bb are roots of t2−9t+18=0=(t−3)(t−6)t^2 - 9t + 18 = 0 = (t-3)(t-6), so {a,b}={3,6}\{a, b\} = \{3, 6\}.

6. The two lines. …

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