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Physics · Ch 12 — Kinetic Theory

Diatomic Gases

12.6.2

Diatomic Gases

The Specific Heat Capacity of Diatomic Gases

The kinetic theory of gases, when applied to diatomic molecules, reveals a richer story than for monatomic gases. A diatomic molecule is not a point particle; it can rotate and vibrate. Each of these additional motions provides a new "store" for energy, and the equipartition theorem tells us exactly how much energy each store holds.

For a diatomic molecule, we consider three distinct types of motion:

  1. Translational motion of the centre of mass (3 degrees of freedom).
  2. Rotational motion about axes perpendicular to the line joining the two atoms (2 degrees of freedom). Rotation about the line joining the atoms (the molecular axis) is neglected because the moment of inertia about that axis is negligible.
  3. Vibrational motion of the two atoms relative to each other (1 degree of freedom for kinetic energy of vibration + 1 degree of freedom for potential energy of vibration = 2 degrees of freedom).

At ordinary temperatures (around room temperature), the vibrational modes are not fully excited. The molecule behaves as a "rigid rotator" — it can translate and rotate, but it does not vibrate. Therefore, at room temperature, a diatomic gas effectively has only 5 active degrees of freedom: 3 translational and 2 rotational.

Important

Active Degrees of Freedom at Room Temperature

For a diatomic gas at ordinary temperatures, the number of active degrees of freedom is f=5f = 5.


Molar Specific Heats for a Diatomic Gas (Rigid Rotator Model)

Using the equipartition theorem, the total internal energy of one mole of a diatomic gas (with f=5f=5) is the sum of the energies in each active degree of freedom.

Each translational degree of freedom contributes 12RT\frac{1}{2}RT per mole.

Each rotational degree of freedom contributes 12RT\frac{1}{2}RT per mole.

Therefore, the total internal energy UU per mole is:

U=3×12RT+2×12RT=52RTU = 3 \times \frac{1}{2}RT + 2 \times \frac{1}{2}RT = \frac{5}{2}RT

From this, we can directly calculate the molar specific heat at constant volume, CVC_V.

Molar Specific Heat at Constant Volume (CVC_V)

CV=dUdT=ddT(52RT)=52RC_V = \frac{dU}{dT} = \frac{d}{dT}\left(\frac{5}{2}RT\right) = \frac{5}{2}R

The molar specific heat at constant pressure, CPC_P, is then found using the universal relation CP−CV=RC_P - C_V = R.

Molar Specific Heat at Constant Pressure (CPC_P)

CP=CV+R=52R+R=72RC_P = C_V + R = \frac{5}{2}R + R = \frac{7}{2}R

Finally, the ratio of specific heats, γ\gamma, is:

Ratio of Specific Heats (γ\gamma)

γ=CPCV=72R52R=75=1.40\gamma = \frac{C_P}{C_V} = \frac{\frac{7}{2}R}{\frac{5}{2}R} = \frac{7}{5} = 1.40

These theoretical values — CV=52RC_V = \frac{5}{2}R, CP=72RC_P = \frac{7}{2}R, and γ=1.40\gamma = 1.40 — agree remarkably well with experimental data for many diatomic gases like hydrogen (H2H_2), nitrogen (N2N_2), and oxygen (O2O_2) at room temperature.

Note

Agreement with Experiment

The excellent agreement between the theoretical predictions (CV=52RC_V = \frac{5}{2}R, γ=1.40\gamma = 1.40) and experimental values for diatomic gases at ordinary temperatures is a powerful validation of the equipartition theorem and the concept of degrees of freedom.


The Role of Vibrational Modes at High Temperatures

What happens when the temperature is raised significantly? The vibrational mode of the molecule becomes active. A diatomic molecule's vibration is like a simple harmonic oscillator. It has two degrees of freedom: one for kinetic energy and one for potential energy. According to equipartition, each contributes 12RT\frac{1}{2}RT, so the vibrational mode contributes a total of RTRT to the molar internal energy.

When vibration is active, the total number of degrees of freedom becomes f=3+2+2=7f = 3 + 2 + 2 = 7. The internal energy per mole is then:

U=32RT+22RT+22RT=72RTU = \frac{3}{2}RT + \frac{2}{2}RT + \frac{2}{2}RT = \frac{7}{2}RT

This leads to the following high-temperature predictions:

CV=dUdT=72RC_V = \frac{dU}{dT} = \frac{7}{2}R

CP=CV+R=92RC_P = C_V + R = \frac{9}{2}R

γ=CPCV=97≈1.29\gamma = \frac{C_P}{C_V} = \frac{9}{7} \approx 1.29

Watch out

The Classical Prediction Fails at High Temperatures

While the classical theory predicts that CVC_V should rise from 52R\frac{5}{2}R to 72R\frac{7}{2}R at high temperatures, this is not observed for most diatomic gases. For example, hydrogen gas (H2H_2) does not show this increase; instead, its CVC_V remains close to 52R\frac{5}{2}R even at very high temperatures. This is a major failure of classical physics. The explanation requires quantum theory, which shows that vibrational energy levels are quantised and require a minimum threshold energy to be excited. At ordinary and even high temperatures, this threshold is often not met, so the vibrational mode remains "frozen out."


The Anomalous Behaviour of Hydrogen at Low Temperatures

Hydrogen (H2H_2) provides a fascinating test case at low temperatures. As the temperature drops, the rotational modes also begin to "freeze out." At very low temperatures (below about 100 K), the hydrogen molecule has insufficient energy to rotate. The only active degrees of freedom are the three translational ones.

In this low-temperature regime, hydrogen behaves like a monatomic gas:

f=3f = 3

U=32RTU = \frac{3}{2}RT

CV=32RC_V = \frac{3}{2}R

γ=53≈1.67\gamma = \frac{5}{3} \approx 1.67

Important

The Temperature Dependence of Degrees of Freedom

The number of active degrees of freedom for a diatomic gas is not a constant. It depends on temperature:

  • Very Low Temperatures: Only translational motion is active (f=3f=3). …