What will the following expression be evaluated to in Python ? print(6/3 + 4**3//8-4) (a) 6.5 (b) 4.0 (c) 6.0

Question 75 of 97

Q. What will the following expression be evaluated to in Python ? print(6/3 + 4**3//8-4)

(a) 6.5

(b) 4.0

(d) 4

Odisha ChseCBSE Class XII Board 2023MCQ· 1mImportance★★★★★

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Precedence: ** first, then / and // left-to-right, then +/-.

print(6/3 + 4**3//8-4)   # 6.0 …

6/3 + 4**3//8 - 4 evaluates as 2.0 + 8 - 4 = 6.0 — a float, because / in Python 3 always returns a float. Correct option: (c) 6.0.

Two rules decide this question:

Precedence: ** (exponent) binds tightest; then / and // (evaluated left to right); + and - come last.
Types: true division / always returns a float in Python 3 (6/3 is 2.0, not 2), while // between two ints returns an int. Any arithmetic mixing a float with an int produces a float.

Step	Sub-expression evaluated	Result	Expression so far
1	`4**3` (highest precedence)	`64`	`6/3 + 64//8 - 4`
2	`6/3` (leftmost of `/`, `//`)	`2.0` (float!)	`2.0 + 64//8 - 4`
3	`64//8`	`8` (int)	`2.0 + 8 - 4`
4	`2.0 + 8`	`10.0`	`10.0 - 4`
5	`10.0 - 4`	`6.0`	`6.0`

Run it:

print(6/3 + 4**3//8-4)

Output:

6.0

Q.What will the following expression be evaluated to in Python ? print(6/3 + 4**3//8-4)