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Chemistry · Ch 1 — Solutions

Summary

Summary

  • Solution: A homogeneous mixture of two or more substances. Solvent is the component in larger amount; solute in smaller.
  • Concentration terms:
    • Mass percentage = mass of solutemass of solution×100\frac{\text{mass of solute}}{\text{mass of solution}} \times 100
    • Mole fraction (xx) = moles of componenttotal moles\frac{\text{moles of component}}{\text{total moles}}
    • Molarity (MM) = moles of solutevolume of solution in L\frac{\text{moles of solute}}{\text{volume of solution in L}}
    • Molality (mm) = moles of solutemass of solvent in kg\frac{\text{moles of solute}}{\text{mass of solvent in kg}}
  • Solubility: Maximum solute that dissolves in a given solvent at a fixed temperature. For gases, follows Henry’s law: p=KH⋅xp = K_H \cdot x (partial pressure ∝\propto mole fraction in liquid).
  • Vapour pressure: For a volatile liquid, it is the pressure of its vapour in equilibrium with the liquid. Raoult’s law: For a solution of volatile liquids, pA=pA∘xAp_A = p_A^\circ x_A and pB=pB∘xBp_B = p_B^\circ x_B; the total vapour pressure is ptotal=p10 x1+p20 x2p_{\text{total}} = p_1^{0}\,x_1 + p_2^{0}\,x_2.
  • Ideal solutions: Obey Raoult’s law at all concentrations; ΔHmix=0\Delta H_{\text{mix}} = 0, ΔVmix=0\Delta V_{\text{mix}} = 0.
  • Non-ideal solutions: Show positive or negative deviations from Raoult’s law; form azeotropes (constant-boiling mixtures).
  • Colligative properties: Depend only on number of solute particles, not their identity:
    • Relative lowering of vapour pressure: p∘−pp∘=xsolute\frac{p^\circ - p}{p^\circ} = x_{\text{solute}}
    • Elevation in boiling point: ΔTb=Kb⋅m\Delta T_b = K_b \cdot m …