The determinant assigns a single number (real or complex) to every square matrix — formally a function f:M→K from the set M of square matrices to the set of numbers K, written f(A)=∣A∣. It encodes key properties, such as whether the matrix is invertible. The determinant of A is denoted ∣A∣, det(A), or Δ (the Greek letter Delta).
For a 2×2 matrix A=[acbd]:
∣A∣=acbd=det(A)
Note
∣A∣ for a determinant is not the modulus (absolute value); for a matrix, ∣A∣ always means the determinant.
Watch out
Only square matrices have determinants — a non-square matrix (e.g. a 2×3 matrix) has none.
Determinant of a 2×2 Matrix
For A=[a11a21a12a22],
det(A)=∣A∣=a11a22−a21a12
the product of the main-diagonal entries minus the product of the other diagonal.
Tip
For [acbd]: the arrow top-left to bottom-right gives a×d, and bottom-left to top-right gives c×b; subtract to get ad−cb.
Determinant of a 3×3 Matrix
For A=a11a21a31a12a22a32a13a23a33, expand along the first row:
Each term is a first-row element, times the sign (+,−,+ across the columns), times the minor — the 2×2 determinant left after deleting that element's row and column.
Important
The sign for the element in row i, column j is (−1)i+j; along the first row this gives +,−,+.
Properties of Determinants
Each property is stated and proved for a 2×2 matrix (the book's approach); the reasoning extends to square matrices of any order.
›Proof
Property 1: det(A)=det(AT).
For A=[acbd], AT=[abcd]: det(A)=ad−bc=ad−cb=det(AT). Holds for all square matrices.
›Proof
Property 2: Interchanging two rows (or columns) changes the sign of the determinant.
Interchanging the rows of A=[acbd] gives B=[cadb]: det(B)=cb−da=−(ad−bc)=−det(A). The same holds for columns.
›Proof
Property 3: Two identical rows (or columns) make the determinant zero.
For A=[aabb], det(A)=ab−ab=0. Likewise for identical columns.
›Proof
Property 4: Multiplying a row (or column) by k multiplies the determinant by k.
Scaling the first row of A=[acbd] gives B=[kackbd]: det(B)=(ka)d−c(kb)=k(ad−bc)=kdet(A).
›Proof
Property 5: A row (or column) written as a sum splits the determinant into two.
For A=[a1+a2cbd], det(A)=(a1+a2)d−cb=(a1d−cb)+(a2d−cb)=a1cbd+a2cbd.
›Proof
Property 6: Adding a multiple of one row (or column) to another leaves the determinant unchanged. …