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Q.State Ohm's law. Calculate the conductivity of a conductor of radius 0.5 mm and length 10 cm having resistance 25 Ω.

Odisha ChseOdisha CHSE +2 Science Board Exam 2020Subjective· 3mImportance★★★★★
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Ohm's law states V=IR at constant temperature; using ρ=RA/L and σ=1/ρ, the conductor's conductivity works out to about 5.1 × 10³ S/m.

Ohm's law: At constant physical conditions (especially constant temperature), the current flowing through a conductor is directly proportional to the potential difference applied across its ends:

V∝I  ⟹  V=IRV \propto I \implies V = IR

where RR, the resistance, is a constant of proportionality for a given conductor at constant temperature.

Calculating conductivity:

Given: radius r=0.5r = 0.5 mm =0.5×10−3= 0.5\times10^{-3} m, length L=10L = 10 cm =0.1= 0.1 m, resistance R=25 ΩR = 25\ \Omega.

Cross-sectional area:

A=πr2=π(0.5×10−3)2=π×0.25×10−6=7.854×10−7 m2A = \pi r^2 = \pi (0.5\times10^{-3})^2 = \pi \times 0.25\times10^{-6} = 7.854\times10^{-7}\ \text{m}^2

Resistivity, from R=ρL/AR = \rho L/A: …

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