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Q.Two wires that are made up of two different materials have specific resistances in the ratio 2:3, lengths 3:4 and areas 4:5. The ratio of their resistances is

(a) 6:5
(b) 6:8
(c) 5:8
(d) 1:2
Odisha ChseOdisha CHSE +2 Science Board Exam 2026MCQ· 1mImportance★★★★★
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Combining the given ratios of resistivity, length and area through R=ρL/AR=\rho L/A gives R1:R2=5:8R_1:R_2 = 5:8.

Resistance of a wire is R=ρLAR = \rho \dfrac{L}{A}, where ρ\rho is resistivity, LL is length and AA is area of cross-section.

Given: ρ1:ρ2=2:3\rho_1:\rho_2 = 2:3, L1:L2=3:4L_1:L_2 = 3:4, A1:A2=4:5A_1:A_2 = 4:5.

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