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Q.If the refractive index of a material of equilateral prism is sqrt(3), then the angle of minimum deviation is

(i) 30 degrees
(ii) 45 degrees
(iii) 60 degrees
(iv) 75 degrees
Odisha ChseOdisha CHSE +2 Science Board Exam 2025MCQ· 1mImportance★★★★★
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Dm = 60 degrees for an equilateral prism with mu = sqrt(3).

The prism formula is μ=sin⁡ ⁣(A+Dm2)sin⁡ ⁣(A2)\mu = \frac{\sin\!\left(\frac{A + D_m}{2}\right)}{\sin\!\left(\frac{A}{2}\right)}. For an equilateral prism A=60∘A = 60^\circ, so sin⁡(A/2)=sin⁡30∘=0.5\sin(A/2) = \sin 30^\circ = 0.5. Then …

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