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Q.Derive the formula mu = sin((A + Dm)/2) / sin(A/2) for a prism. Draw a ray diagram.

Odisha ChseOdisha CHSE +2 Science Board Exam 2025Subjective· 5mImportance★★★★★
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At minimum deviation the path is symmetric, giving r = A/2 and i = (A + Dm)/2, so mu = sin((A+Dm)/2)/sin(A/2).

Ray light passing through triangular glass prism
Ray light passing through triangular glass prism

(A ray diagram is to be drawn - a triangular prism of refracting angle A, with a ray entering face 1 at angle of incidence i1, refracting to r1, crossing to the second face at r2, and emerging at i2; the deviation D is the angle between the incident and emergent rays produced. At minimum deviation the ray inside runs parallel to the base.)

General relations for a prism: For a ray passing through a prism of refracting angle A:

r1+r2=A,D=(i1+i2)−A,r_1 + r_2 = A, \qquad D = (i_1 + i_2) - A,

where D is the angle of deviation.

Condition at minimum deviation: The deviation is minimum when the ray passes symmetrically through the prism, so

i1=i2=i,r1=r2=r.i_1 = i_2 = i, \qquad r_1 = r_2 = r.

From r1+r2=Ar_1 + r_2 = A:   2r=A⇒r=A2\; 2r = A \Rightarrow r = \dfrac{A}{2}.

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