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Worked Examples · Example 13

Q.A man deposits in a bank ₹16,000 at the end of each year, for 8 years. If the rate of interest is 10% per annum compounded annually, what would be the sum standing to his credit at the end of that period?

Puducherry CbseNCERTSubjective· 3mImportance★★★★★est
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✓ Free question

Use the future-value-of-an-ordinary-annuity formula since deposits are made at the end of each year.

FV=R⋅(1+i)n−1iFV=R\cdot\dfrac{(1+i)^{n}-1}{i}, where RR = periodic deposit, ii = interest rate per period, nn = number of periods.

Given: R=₹16,000R=₹16{,}000 per year, i=10%=0.10i=10\%=0.10, n=8n=8 years.

  1. Compute (1.10)8(1.10)^8: 1.102=1.211.10^2=1.21, 1.104=1.46411.10^4=1.4641, 1.108=1.46412=2.143588811.10^8=1.4641^2=2.14358881.
  2. Substitute into the formula:

FV=16000×2.14358881−10.10=16000×1.143588810.10=16000×11.4358881FV=16000\times\dfrac{2.14358881-1}{0.10}=16000\times\dfrac{1.14358881}{0.10}=16000\times11.4358881

  1. Compute:

FV=₹1,82,974.21FV=₹1{,}82{,}974.21

  1. Self-check: total deposits over 8 years =16000×8=₹1,28,000=16000\times8=₹1{,}28{,}000; the extra ₹54,974.21₹54{,}974.21 is the compounded interest earned — reasonable at 10% p.a. over 8 years.
✓Final answer

The sum standing to his credit at the end of 8 years =₹1,82,974.21=₹1{,}82{,}974.21.

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