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Worked Examples · Example 24

Q.A household uses the following appliances daily: a TV (85 Watts) for 4 hours/day, a toaster (1000 Watts) for 15 minutes/day, a kettle (2400 Watts) for 2 hours/day, and 15 light bulbs (100 Watts each) for 5 hours/day. Given a flat rate tariff of 22 paise (cts) per kWh (unit) and a line charge of ₹1.10 per day, calculate the total monthly electricity bill for a 30-day month.

Puducherry CbseNCERTSubjective· 3mImportance★★★★★est
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Compute each appliance's daily energy consumption (in kWh), total it, scale to a 30-day month, apply the per-unit tariff, and add the fixed daily line charge.

Energy (kWh) =Power (W)×Time (hours)1000=\dfrac{\text{Power (W)}\times\text{Time (hours)}}{1000}; Energy Charge == Total Units (kWh) ×\times tariff per unit; Total Bill == Energy Charge ++ Line Charge.

Given (daily use): TV: 85 W for 4 h; Toaster: 1000 W for 15 min (=0.25=0.25 h); Kettle: 2400 W for 2 h; 15 bulbs ×\times 100 W each for 5 h. Tariff =22=22 paise/kWh =₹0.22=₹0.22/kWh. Line charge =₹1.10=₹1.10/day. Month =30=30 days.

  1. Daily energy per appliance (in Wh):
  • TV: 85×4=34085\times4=340 Wh
  • Toaster: 1000×0.25=2501000\times0.25=250 Wh
  • Kettle: 2400×2=48002400\times2=4800 Wh
  • Bulbs: 15×100×5=750015\times100\times5=7500 Wh
  1. Total daily energy:

340+250+4800+7500=12,890 Wh=12.89 kWh/day340+250+4800+7500=12{,}890\ \text{Wh}=12.89\ \text{kWh/day}

  1. Monthly energy (30 days):

12.89×30=386.7 kWh12.89\times30=386.7\ \text{kWh}

  1. Energy charge at ₹0.22/kWh: …

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