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Examples 7.8(b) · Example 5

Q.In a certain language, PAC is coded as 61, how will NEP be coded?

a) 40
b) 66
c) 80
d) 46
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The code is the sum of each letter's position counted from the end of the alphabet (Z=1, Y=2, ..., A=26); verify with PAC=61=61, then compute for NEP.

Reverse alphabet position of a letter in position nn (from A=1,...,Z=26): reverse(n)=27−n\text{reverse}(n) = 27-n.

  1. Find each letter's normal alphabet position: P=16, A=1, C=3P=16,\ A=1,\ C=3.
  2. Convert to reverse position using 27−n27-n: rev(P)=27−16=11\text{rev}(P)=27-16=11; rev(A)=27−1=26\text{rev}(A)=27-1=26; rev(C)=27−3=24\text{rev}(C)=27-3=24.
  3. Sum: 11+26+24=6111+26+24=61, which matches the given code for PAC ✓ — this confirms the rule. …

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