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Exercise 2.1 · Q9

Q.In a restaurant 35 visitors can have lunch at a time. If the number of visitors increases by 7, then the expense of the restaurant on food increases by Rs. 42, while the average expenditure per head decreases by Rs. 1. Find the original expenditure of the restaurant.

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Set up the original and new average-expenditure equations from the given conditions and solve the resulting linear equation for the original total expenditure EE.

Average expenditure per head =Total expenditureNumber of visitors= \dfrac{\text{Total expenditure}}{\text{Number of visitors}}.

  1. Let the original total expenditure on food =₹E= ₹E, for 35 visitors. Original average expenditure per head =E35= \dfrac{E}{35}.
  2. When visitors increase by 7 (to 35+7=4235+7=42), the total expense increases by ₹42, becoming E+42E+42; new average expenditure per head =E+4242= \dfrac{E+42}{42}.
  3. Given: the new average is ₹1 less than the original average: E+4242=E35−1\dfrac{E+42}{42} = \dfrac{E}{35} - 1. …

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