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Exercise 2.4 · Q6

Q.The length and breadth of rectangle are increased by 30% and decreased by 20% respectively. Determine the percentage of increase or decrease in its area.

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Increasing a rectangle's length by 30% and decreasing its breadth by 20% together produce a net 4% increase in area.

Area of a rectangle =Length×Breadth=\text{Length}\times\text{Breadth}. When both dimensions change by percentages, the new area is the product of the individual scale factors times the original area.

  1. Let original length =L=L, original breadth =B=B; original area =LB=LB.
  2. Length increased by 30% ⇒\Rightarrow new length =L(1+0.30)=1.30L=L(1+0.30)=1.30L.
  3. Breadth decreased by 20% ⇒\Rightarrow new breadth =B(1−0.20)=0.80B=B(1-0.20)=0.80B.
  4. New area =1.30L×0.80B=(1.30×0.80)LB=1.04 LB=1.30L\times0.80B=(1.30\times0.80)LB=1.04\,LB. …

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