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NCERT Exemplar · Q18

Q.MnO4^2- undergoes disproportionation reaction in acidic medium but MnO4^- does not. Give reason.

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Disproportionation requires a species to exist in an intermediate oxidation state that can both increase and decrease. MnOX4X2−\ce{MnO4^{2-}} (Mn in +6) can do both in acid, while MnOX4X−\ce{MnO4^-} (Mn in +7, the maximum) can only be reduced.

The heart of this question lies in understanding what disproportionation demands: a single species must simultaneously oxidise and reduce itself. That is only possible when the element sits at an intermediate oxidation state, with room to move both up and down the oxidation ladder.

Manganese exhibits a rich variety of oxidation states, from +2 all the way to +7. The permanganate ion MnOX4X−\ce{MnO4^-} has manganese at +7, the highest stable state for the element. The manganate ion MnOX4X2−\ce{MnO4^{2-}} has manganese at +6, one step below the maximum.

Why MnOX4X2−\ce{MnO4^{2-}} disproportionates in acidic medium

  1. Identify the oxidation state.

    In MnOX4X2−\ce{MnO4^{2-}}, oxygen is −2-2 each, so x+4(−2)=−2  ⟹  x=+6x + 4(-2) = -2 \implies x = +6. Manganese is at +6.

  2. Check for room to move.

    From +6, manganese can:

    • Increase to +7 (forming MnOX4X−\ce{MnO4^-}, permanganate)
    • Decrease to +4 (forming MnOX2\ce{MnO2}, manganese dioxide) or even further to +2 in strongly acidic conditions
  3. The disproportionation reaction.

    In acidic medium, MnOX4X2−\ce{MnO4^{2-}} is unstable and undergoes:

3 MnOX4X2−+4 HX+→2 MnOX4X−+MnOX2+2 HX2O\ce{3 MnO4^{2-} + 4 H^+ -> 2 MnO4^- + MnO2 + 2 H2O}

Here, two of the three Mn(+6) atoms are oxidised to Mn(+7), while one is reduced to Mn(+4). The intermediate oxidation state permits both pathways.

Tip

A quick test for disproportionation: if the oxidation state is neither the minimum nor the maximum for that element, disproportionation is possible (though not always favorable).

Why MnOX4X−\ce{MnO4^-} does not disproportionate

  1. Identify the oxidation state.

    In MnOX4X−\ce{MnO4^-}, we have x+4(−2)=−1  ⟹  x=+7x + 4(-2) = -1 \implies x = +7. Manganese is at its maximum oxidation state.

  2. No room to oxidise further. …

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