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Physics · Ch 1 — Units and Measurement

Rules for Determining Uncertainty in Arithmetic Results

1.3.3

Rules for Determining Uncertainty in Arithmetic Results

Rules for Determining Uncertainty in Arithmetic Results

Product of Measured Quantities

When you multiply measured values, the percentage uncertainties add.

Example: A rectangular sheet has length l=16.2±0.1l = 16.2 \pm 0.1 cm and breadth b=10.1±0.1b = 10.1 \pm 0.1 cm.

The length has three significant figures. The uncertainty of 0.1 cm in 16.2 cm gives a percentage uncertainty of:

0.116.2×100%=0.6%\frac{0.1}{16.2} \times 100\% = 0.6\%

Similarly, the breadth has percentage uncertainty:

0.110.1×100%=1%\frac{0.1}{10.1} \times 100\% = 1\%

The area l×b=163.62l \times b = 163.62 cm². The total percentage uncertainty is 0.6%+1%=1.6%0.6\% + 1\% = 1.6\%.

1.6% of 163.62 cm2=2.6 cm21.6\% \text{ of } 163.62 \text{ cm}^2 = 2.6 \text{ cm}^2

The final result should be reported as:

l×b=164±3 cm2l \times b = 164 \pm 3 \text{ cm}^2

Subtraction Can Reduce Significant Figures

When data are subtracted, the number of significant figures can decrease dramatically.

Example: 12.9 g − 7.06 g. Both numbers are specified to three significant figures. The arithmetic difference is 5.84 g. But the uncertainties combine differently in subtraction — the rule is about decimal places, not significant figures. 12.9 g is correct to one decimal place, so the result should be:

5.8 g5.8 \text{ g}

Not 5.84 g. The subtraction has reduced the precision.

Relative Error Depends on the Number Itself

The relative error of a value specified to nn significant figures depends not only on nn but also on the magnitude of the number.

Example: A mass of 1.02 g measured to ±0.01\pm 0.01 g has a relative error of:

0.011.02×100%=±1%\frac{0.01}{1.02} \times 100\% = \pm 1\%

A mass of 9.89 g measured to ±0.01\pm 0.01 g has a relative error of:

0.019.89×100%=±0.1%\frac{0.01}{9.89} \times 100\% = \pm 0.1\% …