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Exercise B · Q1
Q.

Complete the following table (Order of the matrix):

ABA±BAB
2×22\times 22×22\times 2
2×32\times 33×23\times 2
3×43\times 44×14\times 1
3×33\times 33×33\times 3
2×32\times 32×32\times 3
3×23\times 21×21\times 2
2×32\times 32×32\times 3
1×31\times 33×23\times 2
Puducherry CbseNCERTSubjective· 3mImportance★★★★★est
63% · 50/80 Questions
✓ Free question

Using the rules — A±BA\pm B exists only when A,BA,B have the same order, and ABAB exists only when cols(A)=rows(B)\text{cols}(A)=\text{rows}(B) giving order rows(A)×cols(B)\text{rows}(A)\times\text{cols}(B) — the table is completed below.

For orders A=m×nA=m\times n and B=p×qB=p\times q: A±BA\pm B is defined iff m=p, n=qm=p,\ n=q (result m×nm\times n); ABAB is defined iff n=pn=p (result m×qm\times q). Missing orders are recovered from these conditions.

  1. Row 1: A=2×2, B=2×2A=2\times2,\ B=2\times2. Same order ⇒A±B=2×2\Rightarrow A\pm B=2\times2; cols(A)=rows(B)=2⇒AB=2×2\text{cols}(A)=\text{rows}(B)=2 \Rightarrow AB=2\times2.
  2. Row 2: A=2×3, B=3×2A=2\times3,\ B=3\times2. Different orders ⇒A±B\Rightarrow A\pm B not defined; cols(A)=3=rows(B)⇒AB=2×2\text{cols}(A)=3=\text{rows}(B) \Rightarrow AB=2\times2.
  3. Row 3: A=3×4, B=4×1A=3\times4,\ B=4\times1. Different ⇒A±B\Rightarrow A\pm B not defined; cols(A)=4=rows(B)⇒AB=3×1\text{cols}(A)=4=\text{rows}(B) \Rightarrow AB=3\times1.
  4. Row 4: A=3×3, B=3×3A=3\times3,\ B=3\times3. Same ⇒A±B=3×3\Rightarrow A\pm B=3\times3; AB=3×3AB=3\times3.
  5. Row 5: A=2×3, A±B=2×3A=2\times3,\ A\pm B=2\times3. So BB must match A⇒B=2×3A \Rightarrow B=2\times3; then cols(A)=3≠rows(B)=2⇒AB\text{cols}(A)=3\neq\text{rows}(B)=2 \Rightarrow AB not defined.
  6. Row 6: B=3×2, AB=1×2B=3\times2,\ AB=1\times2. rows(A)=rows(AB)=1\text{rows}(A)=\text{rows}(AB)=1 and cols(A)=rows(B)=3⇒A=1×3\text{cols}(A)=\text{rows}(B)=3 \Rightarrow A=1\times3; A±BA\pm B (different orders) not defined.
  7. Row 7: same as Row 5 ⇒B=2×3\Rightarrow B=2\times3, A±B=2×3A\pm B=2\times3, ABAB not defined.
  8. Row 8: A=1×3, B=3×2A=1\times3,\ B=3\times2. Different ⇒A±B\Rightarrow A\pm B not defined; cols(A)=3=rows(B)⇒AB=1×2\text{cols}(A)=3=\text{rows}(B) \Rightarrow AB=1\times2.

Completed table:

ABA±BAB
2×22\times22×22\times22×22\times22×22\times2
2×32\times33×23\times2Not defined2×22\times2
3×43\times44×14\times1Not defined3×13\times1
3×33\times33×33\times33×33\times33×33\times3
2×32\times32×32\times32×32\times3Not defined
1×31\times33×23\times2Not defined1×21\times2
2×32\times32×32\times32×32\times3Not defined
1×31\times33×23\times2Not defined1×21\times2
✓Final answer

See the completed table above — the recovered missing orders are B=2×3B=2\times3 (rows 5 and 7) and A=1×3A=1\times3 (row 6); A±BA\pm B is undefined whenever the two orders differ, and ABAB follows rows(A)×cols(B)\text{rows}(A)\times\text{cols}(B).

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