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3.1 · Q4

Q.If the marginal revenue function of a firm in the production of output is MR=40−10x2MR = 40 - 10x^2 where xx is the level of output and total revenue is ₹120 at 3 units of output, find the total revenue function.

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Integrate MRMR to get R(x)R(x), then use R(3)=₹120R(3)=₹120 to fix the constant: R(x)=40x−10x33+90R(x)=40x-\dfrac{10x^3}{3}+90.

Total revenue R(x)=∫MR dxR(x)=\displaystyle\int MR\,dx, with the constant of integration fixed by the given condition R(x1)=R1R(x_1)=R_1.

  1. R(x)=∫(40−10x2) dx=40x−10x33+C.R(x)=\displaystyle\int (40-10x^2)\,dx=40x-\frac{10x^3}{3}+C.
  2. Apply R(3)=120R(3)=120: 40(3)−10(3)33+C=120−2703+C=120−90+C=30+C.40(3)-\dfrac{10(3)^3}{3}+C=120-\dfrac{270}{3}+C=120-90+C=30+C. …

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