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Worked Examples · Example 7

Q.Identify the following expressions as Rational Functions. Further classify them as Proper or Improper. If Improper, express them as sum of a polynomial and proper rational function.

(a) 1−3x2+4x−5\frac{1}{-3x^2+4x-5}
(b) x(x+1)(2x+3)\frac{\sqrt{x}}{(x+1)(2x+3)}
(c) (x+1)(x+2)(x+3)(x+4)\frac{(x+1)(x+2)}{(x+3)(x+4)}
Puducherry CbseNCERTSubjective· 3mImportance★★★★★est
12% · 7/59 Questions
✓ Free question

A rational function is a ratio of two polynomials; it is proper if deg⁡(num)<deg⁡(den)\deg(\text{num})<\deg(\text{den}), improper otherwise — an improper one is split by division into polynomial + proper part.

f(x)=P(x)Q(x), P,Q polynomials;proper  ⟺  deg⁡P<deg⁡Q.f(x)=\frac{P(x)}{Q(x)},\ P,Q\text{ polynomials};\quad \text{proper}\iff \deg P<\deg Q.

Steps

  1. (a) 1−3x2+4x−5\dfrac{1}{-3x^2+4x-5}: numerator degree 00, denominator degree 22 (both polynomials). It is rational and 0<20<2, so it is proper.

  2. (b) x(x+1)(2x+3)\dfrac{\sqrt{x}}{(x+1)(2x+3)}: the numerator x=x1/2\sqrt{x}=x^{1/2} has a fractional power, so it is not a polynomial. Therefore the expression is not a rational function, and proper/improper does not apply.

  3. (c) (x+1)(x+2)(x+3)(x+4)=x2+3x+2x2+7x+12\dfrac{(x+1)(x+2)}{(x+3)(x+4)}=\dfrac{x^2+3x+2}{x^2+7x+12}: both are polynomials of degree 22, so it is rational and, since deg⁡num=deg⁡den\deg\text{num}=\deg\text{den}, improper. Divide:

x2+3x+2x2+7x+12=1+(x2+3x+2)−(x2+7x+12)x2+7x+12=1+−4x−10x2+7x+12.\frac{x^2+3x+2}{x^2+7x+12}=1+\frac{(x^2+3x+2)-(x^2+7x+12)}{x^2+7x+12}=1+\frac{-4x-10}{x^2+7x+12}.

=1−4x+10(x+3)(x+4)(a polynomial 1 plus a proper rational function).=1-\frac{4x+10}{(x+3)(x+4)}\quad(\text{a polynomial }1\text{ plus a proper rational function}).

✓Final answer

  1. rational, proper;
  2. not rational (x\sqrt{x});
  3. rational, improper =1−4x+10(x+3)(x+4)=1-\dfrac{4x+10}{(x+3)(x+4)}.

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