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Miscellaneous · Q4

Q.A firm finds that quantity demanded and quantity supplied are 30 units when market price is ₹8 per unit. Further, if price is increased to ₹12 per unit, demand reduces to 0 and at a price of ₹5 per unit, the firm is not willing to produce. Assuming the linear relationship between price and quantity in both cases, find the demand function, supply function and consumers' surplus and producers' surplus at equilibrium price.

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Fit the two straight lines through the given price–quantity points, confirm equilibrium at q=30, p=₹8q=30,\ p=\text{₹}8, then integrate to get CS=₹60CS=\text{₹}60 and PS=₹45PS=\text{₹}45.

Straight line through (q1,p1),(q2,p2)(q_1,p_1),(q_2,p_2): p−p1=p2−p1q2−q1(q−q1)p-p_1=\dfrac{p_2-p_1}{q_2-q_1}(q-q_1).

CS=∫0q0pd(q) dq−p0q0,PS=p0q0−∫0q0ps(q) dq,\displaystyle CS=\int_0^{q_0}p_d(q)\,dq-p_0q_0,\qquad PS=p_0q_0-\int_0^{q_0}p_s(q)\,dq, where pd,psp_d,p_s are the demand and supply price functions and (q0,p0)(q_0,p_0) is equilibrium.

Demand function — points (q,p)=(30,8)(q,p)=(30,8) and (0,12)(0,12) (demand 00 at ₹12):

  1. Slope =12−80−30=−215=\dfrac{12-8}{0-30}=-\dfrac{2}{15}.
  2. p−12=−215(q−0)⇒pd=12−215qp-12=-\dfrac{2}{15}(q-0)\Rightarrow \boxed{p_d=12-\dfrac{2}{15}q} (check: q=30⇒p=12−4=8q=30\Rightarrow p=12-4=8 ✓).

Supply function — points (30,8)(30,8) and (0,5)(0,5) (supplies 00 at ₹5):

3. Slope =8−530−0=110=\dfrac{8-5}{30-0}=\dfrac{1}{10}.

4. p−5=110(q−0)⇒ps=5+q10p-5=\dfrac1{10}(q-0)\Rightarrow \boxed{p_s=5+\dfrac{q}{10}} (check: q=30⇒p=5+3=8q=30\Rightarrow p=5+3=8 ✓).

Equilibrium — set pd=psp_d=p_s:

5. 12−215q=5+q10⇒7=q(110+215)=q⋅730⇒q0=30, p0=₹8.12-\dfrac{2}{15}q=5+\dfrac{q}{10}\Rightarrow 7=q\Big(\dfrac1{10}+\dfrac{2}{15}\Big)=q\cdot\dfrac{7}{30}\Rightarrow q_0=30,\ p_0=\text{₹}8.

Consumers' surplus: …

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