Q.What will be the output of the following code ? def f1(a,b=1): print(a+b,end='-') c=f1(1,2) print(c,sep='') (A) 3-2 (B) 3-2 (C) 3-None (D) 3*None-

Concept: Function return values and print() behavior in Python.

The function f1 prints a+b with end='-' but has no explicit return statement, so it returns None by default.

Step-by-step execution:

1. c = f1(1,2) calls f1 with a=1, b=2. Inside, print(1+2, end='-') outputs 3- (no newline, dash instead).
2. The function completes without returning anything, so c is assigned None. …

When a Python function has no explicit return, it returns None. This question tests the difference between what a function prints and what it returns, and how print handles None and its keyword arguments.

The function f1(a, b=1) computes a+b and prints it with end='-' instead of a newline. There is no return, so calling f1(1,2) prints the sum and evaluates to None, which is then assigned to c.

Trace of the execution:

1. Call f1(1, 2) — inside, a=1 and b=2, so a+b is 3.

2. print(a+b, end='-') — outputs 3 and, instead of a newline, ends with -. So far the console shows:

   3-
   

3. Function returns None — with no return statement, f1 returns None, so c = f1(1,2) stores None in c. …