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Chemistry · Ch 7 — Alcohols, Phenols and Ethers

Preparation of Phenols

7.4.2

Preparation of Phenols

Phenol was first isolated in the early nineteenth century from coal tar, where it was known as carbolic acid. Today it is produced synthetically on an industrial scale. In the laboratory, phenols are typically built up from benzene derivatives by one of four routes.

1. From Haloarenes

Chlorobenzene is fused with sodium hydroxide under forcing conditions — around 623 K and a pressure of roughly 320 atmospheres. Because the C–Cl bond of a haloarene is normally very unreactive toward nucleophilic substitution (the lone pair on chlorine is delocalised into the ring, and the ring itself resists nucleophilic attack), only such extreme temperature and pressure can drive the hydroxide ion in to displace chloride. This gives sodium phenoxide, which is then acidified to liberate phenol.

Preparation of phenol from chlorobenzene: fusion with NaOH at 623 K and 300 atm gives sodium phenoxide, which on acidification with HCl yields phenol, drawn with Kekule benzene rings as in the NCERT scheme.
Preparation of phenol from chlorobenzene: fusion with NaOH at 623 K and 300 atm gives sodium phenoxide, which on acidification with HCl yields phenol, drawn with Kekule benzene rings as in the NCERT scheme.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (Cl, ŌNa⁺, OH) and reagent placement exactly as the …

2. From Benzenesulphonic Acid

Benzene is first sulphonated with oleum to give benzenesulphonic acid. This is converted to sodium phenoxide by fusing it with molten sodium hydroxide, and acidifying the resulting sodium salt then gives phenol.

Preparation of phenol from benzenesulphonic acid: benzene is sulphonated with oleum to benzenesulphonic acid, which is fused with NaOH and then acidified to give phenol, drawn with Kekule benzene rings as in the NCERT scheme.
Preparation of phenol from benzenesulphonic acid: benzene is sulphonated with oleum to benzenesulphonic acid, which is fused with NaOH and then acidified to give phenol, drawn with Kekule benzene rings as in the NCERT scheme.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (SO3H, OH) and reagent placement exactly as the t …

3. From Diazonium Salts

An aromatic primary amine, such as aniline, is treated with nitrous acid (generated in situ from NaNO2\text{NaNO}_2 and HCl) at a low temperature of 273–278 K to form a diazonium salt. Warming this diazonium salt with water — or treating it with dilute acid — hydrolyses it to a phenol, with loss of nitrogen gas.

Preparation of phenol from a diazonium salt: aniline is diazotised with NaNO2 and HCl to benzene diazonium chloride, which on warming with water is hydrolysed to phenol with loss of N2 and HCl, drawn with Kekule benzene rings and the printed compound names.
Preparation of phenol from a diazonium salt: aniline is diazotised with NaNO2 and HCl to benzene diazonium chloride, which on warming with water is hydrolysed to phenol with loss of N2 and HCl, drawn with Kekule benzene rings and the printed compound names.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (NH2, N2⁺Cl⁻, OH) and reagent placement exactly as the …

The low-temperature diazotisation step is essential — the diazonium salt is only stable when cold, and the same salt is what undergoes hydrolysis to the phenol once warmed.

4. From Cumene (The Cumene Process)

Most of the world's phenol is manufactured today not by any of the three laboratory routes above, but by a large-scale industrial sequence built around cumene (isopropylbenzene).

Step 1 — making cumene. Cumene itself is obtained by alkylating benzene with propene under Friedel–Crafts conditions (an acid catalyst such as anhydrous AlCl3\text{AlCl}_3 or a solid-acid catalyst), which attaches an isopropyl group directly onto the benzene ring.

C6H6  +  CH2 ⁣= ⁣CH–CH3    ⟶AlCl3    C6H5–CH(CH3)2(Cumene)\text{C}_6\text{H}_6 \; + \; \text{CH}_2\!=\!\text{CH–CH}_3 \;\; \overset{\text{AlCl}_3}{\longrightarrow} \;\; \text{C}_6\text{H}_5\text{–CH(CH}_3)_2 \quad (\text{Cumene})

Step 2 — air oxidation to the hydroperoxide. Cumene is then oxidised with air (oxygen) under controlled conditions. Oxidation occurs selectively at the benzylic C–H bond, since the resulting radical is stabilised by the adjacent aromatic ring, and the product is cumene hydroperoxide.

C6H5–CH(CH3)2  +  O2  ⟶  C6H5–C(CH3)2–O–O–H(Cumene hydroperoxide)\text{C}_6\text{H}_5\text{–CH(CH}_3)_2 \; + \; \text{O}_2 \;\longrightarrow\; \text{C}_6\text{H}_5\text{–C(CH}_3)_2\text{–O–O–H} \quad (\text{Cumene hydroperoxide})

Step 3 — acid-catalysed rearrangement and cleavage. Treating cumene hydroperoxide with dilute acid triggers a rearrangement: the O–O bond is protonated and cleaved, and the phenyl group migrates from carbon to the adjacent electron-deficient oxygen almost simultaneously with the loss of water. The resulting oxocarbenium species is then captured by water and fragments to give phenol and acetone directly.

The cumene process for phenol: cumene (isopropylbenzene) is oxidised by air (O2) to cumene hydroperoxide, which on treatment with dilute acid gives phenol and acetone, drawn with Kekule benzene rings and the printed compound names.
The cumene process for phenol: cumene (isopropylbenzene) is oxidised by air (O2) to cumene hydroperoxide, which on treatment with dilute acid gives phenol and acetone, drawn with Kekule benzene rings and the printed compound names.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (CH3, –CH, –C, –O, –H, OH) and reagent placement exactly as th …

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