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Exercises · 1.37
Q.

Vapour pressures of pure acetone and chloroform at 328 K are 741.8 mm Hg and 632.8 mm Hg respectively. Assuming that they form ideal solution over the entire range of composition, plot ptotalp_{total}, pchloroformp_{chloroform}, and pacetonep_{acetone} as a function of xacetonex_{acetone}. The experimental data observed for different compositions of mixture is:

100×xacetone100 \times x_{acetone}0011.811.823.423.436.036.050.850.858.258.264.564.572.172.1
pacetonep_{acetone} /mm Hg0054.954.9110.1110.1202.4202.4322.7322.7405.9405.9454.1454.1521.1521.1
pchloroformp_{chloroform} /mm Hg632.8632.8548.1548.1469.4469.4359.7359.7257.7257.7193.6193.6161.2161.2120.7120.7

Plot this data also on the same graph paper. Indicate whether it has positive deviation or negative deviation from the ideal solution.

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We calculate ideal vapor pressures using Raoult's Law and compare them with the given experimental data. The experimental partial and total vapor pressures are consistently lower than the ideal values, indicating a negative deviation from Raoult's Law.

When two volatile liquids mix, the vapor pressure of the resulting solution depends on the mole fractions of the components and their pure vapor pressures. For an ideal solution, this relationship is described by Raoult's Law. Real solutions, however, often deviate from this ideal behavior due to differences in intermolecular forces.

Concept: Raoult's Law and Deviations

  1. Raoult's Law for Ideal Solutions: For an ideal solution, the partial vapor pressure of each component (pAp_A) in the solution is directly proportional to its mole fraction (xAx_A) in the liquid phase and its vapor pressure in the pure state (PA0P^0_A).

    pA=xAPA0p_A = x_A P^0_A

    pB=xBPB0p_B = x_B P^0_B

  2. Dalton's Law of Partial Pressures: The total vapor pressure (ptotalp_{total}) of the solution is the sum of the partial vapor pressures of its components.

    ptotal=pA+pB=xAPA0+xBPB0p_{total} = p_A + p_B = x_A P^0_A + x_B P^0_B

    Since xA+xB=1x_A + x_B = 1, we can also write ptotal=xAPA0+(1−xA)PB0p_{total} = x_A P^0_A + (1 - x_A) P^0_B. This shows that for an ideal solution, the total vapor pressure varies linearly with the mole fraction of one component.

  3. Deviations from Ideal Behavior: Real solutions deviate from Raoult's Law when the intermolecular forces between unlike molecules (A-B) are different from those between like molecules (A-A and B-B).

    • Positive Deviation: Occurs when A-B interactions are weaker than A-A and B-B interactions. Molecules escape more easily into the vapor phase, leading to higher partial and total vapor pressures than predicted by Raoult's Law.
    • Negative Deviation: Occurs when A-B interactions are stronger than A-A and B-B interactions. Molecules are held more tightly in the liquid phase, making it harder for them to escape. This results in lower partial and total vapor pressures than predicted by Raoult's Law.

To determine the deviation, we first calculate the ideal vapor pressures using Raoult's Law for various compositions and then compare these theoretical values with the experimentally observed values.

Step-by-Step Solution

1. Identify Given Data

We are given the pure vapor pressures at 328 K:

  • Vapor pressure of pure acetone (Pacetone0P^0_{acetone}) = 741.8 mm Hg
  • Vapor pressure of pure chloroform (Pchloroform0P^0_{chloroform}) = 632.8 mm Hg

We are also provided with experimental data for different compositions:

100×xacetone100 \times x_{acetone}xacetonex_{acetone}Experimental pacetonep_{acetone} (mm Hg)Experimental pchloroformp_{chloroform} (mm Hg)
000632.8
11.80.11854.9548.1
23.40.234110.1469.4
36.00.360202.4359.7
50.80.508322.7257.7
58.20.582405.9193.6
64.50.645454.1161.2
72.10.721521.1120.7
2. Calculate Ideal Partial and Total Vapor Pressures

Using Raoult's Law, we calculate the ideal partial pressures for acetone and chloroform, and then the ideal total pressure for each given composition. We also calculate the experimental total pressure by summing the experimental partial pressures.

  • Ideal pacetone=xacetone×Pacetone0p_{acetone} = x_{acetone} \times P^0_{acetone}
  • Ideal pchloroform=xchloroform×Pchloroform0p_{chloroform} = x_{chloroform} \times P^0_{chloroform} (where xchloroform=1−xacetonex_{chloroform} = 1 - x_{acetone})
  • Ideal ptotal=Ideal pacetone+Ideal pchloroformp_{total} = \text{Ideal } p_{acetone} + \text{Ideal } p_{chloroform}
  • Experimental ptotal=Experimental pacetone+Experimental pchloroformp_{total} = \text{Experimental } p_{acetone} + \text{Experimental } p_{chloroform}

Here is a table summarizing the calculated ideal values alongside the experimental data:

xacetonex_{acetone}xchloroformx_{chloroform}Ideal pacetonep_{acetone} (mm Hg)Ideal pchloroformp_{chloroform} (mm Hg)Ideal ptotalp_{total} (mm Hg)Experimental pacetonep_{acetone} (mm Hg)Experimental pchloroformp_{chloroform} (mm Hg)Experimental ptotalp_{total} (mm Hg)
010632.8632.80632.8632.8
0.1180.88287.5558.2645.754.9548.1603.0
0.2340.766173.6485.0658.6110.1469.4579.5
0.3600.640267.0405.0672.0202.4359.7562.1
0.5080.492376.8311.3688.2322.7257.7580.4
0.5820.418431.8264.5696.3405.9193.6599.5
0.6450.355478.5224.6703.1454.1161.2615.3
0.7210.279534.8176.5711.3521.1120.7641.8
10741.80741.8(741.8)(0)(741.8)
3. Plot the Data …

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