Q.An edge of a variable cube is increasing at the rate of . How fast is the volume of the cube increasing when the edge is long?
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Start your 14-day free trial to unlock the full solution →We use related rates: the volume changes at . With cm/s and cm, the volume increases at cm³/s.
This is a classic related rates problem — a staple in calculus. The idea is simple: when one quantity (the edge length ) changes with time, another quantity that depends on it (the volume ) also changes. We connect their rates of change using differentiation with respect to time .
The key step is always: write the relationship between the quantities, then differentiate both sides with respect to time. Do not plug in the given numbers until after you differentiate — that’s a common trap.
- Write the relationship. For a cube of edge length , the volume is
- Differentiate with respect to time . Since both and are functions of , we use the chain rule:
This equation tells us: the rate at which volume grows depends on the current edge length and the rate at which the edge itself grows.
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Identify the given rates and the instant.
We are told:
- cm/s (constant rate of increase of the edge).
- We want when cm.
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Substitute the values.
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