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NCERT Exemplar · Q55

Q.(xi) The differential equation of all non-horizontal lines in a plane is d2xdy2=0\frac{d^2x}{dy^2}=0. (State True or False.)

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The order of a differential equation is the highest derivative present. For non-horizontal lines, the equation d2xdy2=0\frac{d^2x}{dy^2}=0 is indeed of order 2, but the statement is about whether this equation is the differential equation of all non-horizontal lines — and it is True.

The question asks you to judge a statement: "The differential equation of all non-horizontal lines in a plane is d2xdy2=0\frac{d^2x}{dy^2}=0." This is a True/False problem, but it tests a deeper understanding of what a differential equation represents and how we derive it from a family of curves.

Let's break it down.

  1. What does "non-horizontal lines" mean?

    A horizontal line has the form y=cy = c (constant slope zero). A non-horizontal line is any line that is not parallel to the x-axis — so it can be written as y=mx+cy = mx + c with m≠0m \neq 0, or equivalently as x=py+qx = py + q (where p≠0p \neq 0). The second form is more useful here because the given equation uses derivatives with respect to yy.

  2. Why consider xx as a function of yy?

    Usually we write y=f(x)y = f(x), but for a vertical line (x=constantx = \text{constant}) the slope dydx\frac{dy}{dx} is undefined. However, the problem specifically says non-horizontal lines — vertical lines are allowed. To include vertical lines, we treat xx as a function of yy. A non-horizontal line can always be written as x=ay+bx = ay + b, where a,b∈Ra, b \in \mathbb{R} are constants — this includes a=0a=0, which gives the vertical line x=bx=b (still non-horizontal). So the family is x=ay+bx = ay + b, with a,b∈Ra, b \in \mathbb{R}.

  3. Derive the differential equation.

    Differentiate x=ay+bx = ay + b with respect to yy:

dxdy=a\frac{dx}{dy} = a

Differentiate again:

d2xdy2=0\frac{d^2x}{dy^2} = 0

This is a second-order differential equation. It has no arbitrary constants left — we eliminated both aa and bb by differentiating twice. So every non-horizontal line satisfies d2xdy2=0\frac{d^2x}{dy^2}=0.

  1. But is the converse true? …

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